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Unary Operator Expected Error In Shell Script

December 17, 2017 • Andre

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Using variables with the value of "7" and "3", AWK returns the following results for each operator when using the print command:

When you run this script, it should output the line "Number equals 1" because, well, number equals 1. If you don’t get the expected output, check your typing; you.

The script is below. I am receiving an error that states logscript:. unary operator expected. (nor what shell you are using or what operating system).

To resolve this issue, I use a more advanced backup script. to the shell, enter the following command — note that I assume the user will be called "backupuser" and that there are double dashes for the switches: localaccounts.user.add.

Shell script is not working due to unary operator expected error. Dear friends, I have a problem to write a shell script which is containing the case function.

. line 16: [: -eq: unary operator expected. where I am trying to display the result gives the error. Browse other questions tagged shell-script or ask.

perlop. NAME DESCRIPTION. Operator Precedence and Associativity Terms and List Operators (Leftward) The Arrow Operator Auto-increment and Auto-decrement

Objective. Learn how to define and use variables in shell script. Learn how shells (bash) structured language constructs.

BSD, Linux, and UNIX shell scripting — Post awk, bash, csh, ksh, perl, php, python, sed, sh, shell scripts, and other shell scripting languages questions here.

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May 3, 2016. The variable used is empty, leading to the error message regarding unary operator. Possible reason could be there is no rootfs in df -H output i.e. in your system. $ foo= $ [ $foo -gt 10 ] && echo OK bash: [: -gt: unary operator expected. You have also some other issues in your script, the OR logic should be.

I have this in my shell script. read -p "Number ? " choice ; tput cuu1. Placing quotes around things removes the "unary operator expected" message when just pressing enter. read -p. I then put quotation marks around it but the error message just changed to something like "integer expected". Well i have.

and run the script again. This time you should get the following: [[email protected] me]$./trouble.bash /trouble.bash: [: =: unary operator expected. Number does not equal 1. As you can see, bash displayed an error message when we ran the script. You probably think that by removing the "1" on line 3 it created a syntax error on.

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test command or [ expr ] test command or [ expr ] is used to see if an expression is true, and if it is true it return zero(0), otherwise returns nonzero for false.

I use an if statement but I keep getting the unary operator expected error. Bash script error [: !=: unary operator. Getting unary operator error on Shell.

Hi I am doing a script like if [ \$table_name != 'ABC' ] then echo 'table name dosent exist' exit fi the problem is if \$table_name is null then i am getting the error [: =: unar.

unary operator expected in shell script when comparing null. – I have two variables var="" var1=abcd Here is my shell script code if [ $var == $var1 ]; then do something else do something fi If I run this code it will prompt.

Check out my other tutorials on the Unix Page, and my. Check my blog Table of Contents. C shell problems; Quoting long strings, $ and ! The ad hoc parser

I only remember one practical writing lesson from my three years as an English major: Whenever you can, put the best bits at the end of the sentence. Put the next-best bits at the beginning, and put the rest in the middle. This trick works in.

Mar 23, 2015. That error is because LOG_LEVEL is not defined. You haven't given us any information at all about how you're running this function (nor what shell you are using or what operating system) but the error will go away if LOG_LEVEL is set. For example: $ foo=""; [ 1 -le $foo ] && echo yes bash: [: 1: unary.

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